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0.810x^2-3.43x+1.62=0
a = 0.810; b = -3.43; c = +1.62;
Δ = b2-4ac
Δ = -3.432-4·0.810·1.62
Δ = 6.5161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.43)-\sqrt{6.5161}}{2*0.810}=\frac{3.43-\sqrt{6.5161}}{1.62} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.43)+\sqrt{6.5161}}{2*0.810}=\frac{3.43+\sqrt{6.5161}}{1.62} $
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